如何处理免费的(c)中的错误? [英] How to handle free() errors in C?
问题描述
假设我使用了一个免费()
函数来释放,原因是多方面的,我不能到存储。
如何从崩溃阻止我的C程序,只是生成一个错误,并继续执行?我没有的try-catch样的规定在这里(如C ++ / Java的...)。有没有办法忽略此错误并继续执行?
Suppose that I have used a free()
function to free a memory that,for many reasons, I'm not allowed to.
How can I stop my C application from crashing and just generate an error and continue the execution? I don't have try-catch kind of provision here (like C++/java...). Is there any way to ignore this error and continue execution?
如果是,
- 你是怎么做到的?
- 更重要的是,它是最好这样做(继续执行考虑这发生内存错误)?
感谢您
推荐答案
有什么也没有,你可以使用你想要的C标准。在免费
功能的描述是说的很清楚(在C99§7.20.3.2):
There is nothing in the C standard that you can use to do what you want. The description of the free
function is very clear on that (§7.20.3.2 in C99):
自由功能使空间ptr指向要被释放,也就是说,国产
可用于进一步分配。若ptr为空指针,不会发生任何操作。的否则,如果
参数不匹配的释放calloc,malloc的早期返回一个指针,或
realloc函数,或者如果空间已释放通过调用免费或realloc,
的行为是理解过程网络定义。 的
The free function causes the space pointed to by ptr to be deallocated, that is, made available for further allocation. If ptr is a null pointer, no action occurs. Otherwise, if the argument does not match a pointer earlier returned by the calloc, malloc, or realloc function, or if the space has been deallocated by a call to free or realloc, the behavior is undefined.
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