更改位C中的诠释？ [英] Changing bits in an int in C?

问题描述

所以我有一个16位的数字。说，对于它的变量名是位。我想要让这个位[2：0] = 001，100，万和，在不改变任何东西。我不知道如何做到这一点，因为所有我能想到的是或运算位我想成为一个1 1，但我不知道如何让他们为0。如果有人清除其他位有建议，我倒是AP preciate它。谢谢！

So I have a 16 bit number. Say that the variable name for it is Bits. I want to make it so that Bits[2:0] = 001, 100, and 000, without changing anything else. I'm not sure how to do it, because all I can think of is ORing the bit I want to be a 1 with 1, but I'm not sure how to clear the other bits so that they're 0. If anyone has advice, I'd appreciate it. Thanks!

推荐答案

要清除某些位，＆安培; 与位的倒数被清除。然后你可以 | 在您需要的位

To clear certain bits, & with the inverse of the bits to be cleared. Then you can | in the bits you want.

在这种情况下，你要零出低三位（十进制111 二进制或 7 ），所以我们＆放大器; 与〜7 来清除这些位

In this case, you want to zero out the lower three bits (111 in binary or 7 in decimal), so we & with ~7 to clear those bits.

Bits = (Bits & ~7) | 1; // set lower three bits of Bits to 001

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