集整数值位掩码 [英] set integer value as bit mask

问题描述

什么是指定位掩码为整数值简单的方​​法？
比如我要与第一，第三和第四位= 1的整数，其他= 0。

What is simplest way to assign a bit mask to integer value? For example I want integer with first, third and forth bits = 1, other = 0.

当然，我找了code，而不是单一的价值！肯定有很多可能性，但我试图找到最简单，最描述寻找

Certainly I am looking for code, not for single value! And certainly there lot of possibilities, but I try to find simplest and most descriptive looking

推荐答案

我觉得认为最好的办法是从0到刚刚指数位，然后应用以设置为N（！）：个位，按位或用值（1 <<;＆所述; n）的

I think the best way to think (!) is to just index bits from 0, and then apply "to set the n:th bit, bitwise-OR with the value (1 << n)":

int first_third_and_fourth = (1 << 0) | (1 << 2) | (1 << 3);

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