“{”令牌C程序之前预期的前pression [英] expected expression before ‘{’ token c program

问题描述

编译code的这一部分时，我写以下code我解决一个难题我

I wrote following code I am solving a puzzle I when compiled this part of code

#include <stdio.h>
int main ()
{

int a[10],b[10],c[10];
int i,j,k,l;
 a[10]={"21","33","12","19","15","17","11","12","34","10"};
 b[10]={"10","15","9","13","16","21","15","32","29","7"};
 c[10]={"11","8","3","6","1","4","6","20","19","3"};

 l=sizeof(a)/sizeof(a[0]);

for (i=0;i<=l;i++)
 {
 }
}

给我误差

array.c: In function ‘main’:
array.c:7:8: error: expected expression before ‘{’ token
array.c:8:8: error: expected expression before ‘{’ token
array.c:9:8: error: expected expression before ‘{’ token

为什么错误来这里？

Why is the error coming here?

推荐答案

有在你的code以下几个问题：

There's several problems in your code:

1. 您应该初始化数组在同一行声明它们


2. 您必须使用数字数组初始化它们，而不是与C-字符串数组：


3. 您实际尝试值设置为数组的元素11'th。

code的正确的路线将是：

Correct line of code will be:

int a[10] = {21,33,12,19,15,17,11,12,34,10};

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