C的误差:之前的预期前pression'||'象征 [英] C error: expected expression before '||' token

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问题描述

下面是我的code的功能合并:

Here is my code for the function merge:

    #include <stdio.h>
    #include "merge.h"


void merge(
    char a1[], int n1,
    char a2[], int n2,
    char output[])
{
    int i = 0;
    int j = 0;
    int z = 0;

    while (i < n1) || (j < n2)  // This is where the error happends
    {
        if (i < n1) && (j < n2)
        if (a1[i] <= a2[j])
                output[z++] = a1[i++];
        else
            output[z++] = a2[j++];

        else if (j == n2)
         while (i < n1)
              output[z++] = a1[i++];

    else if (i == n1)
         while (j < n2)
              output[z++] = a2[j++];
     }
}

您能告诉我为什么code的这个错误?我已经看了所有与此相同的错误问题,但它似乎像有这个错误没有统一的答案...
非常感谢!

Could you tell me why the code has this error? I have looked at all the questions with this same error but it seems like there was no universal answer for this error... Thanks a lot!

推荐答案

Englobe括号之间的充分条件:

Englobe the full condition between brackets:

while ((i < 3) || (j < 3)) 

您也可以使用:

while (i < 3 || j < 3)

和与认真:

if (i < n1) && (j < n2)

其可以是:

if (i < n1 && j < n2)

这篇关于C的误差:之前的预期前pression'||'象征的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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