使用函数二维数组扫描对 [英] 2D array using a function to scan for pairs

问题描述

我创造了这个功能，它可以扫描一个二维数组用于垂直对，其中行= 20，列= 30从澄清随机字符到Z存储在每个数组的元素。

I created this function that scans a 2D array for vertical pairs, where row = 20 and column = 30. To clarify random characters from A to Z are stored in each of the array's elements.

char function3 (char randchar_array[ROW] [COLUMN]) 

{
int r = 0 ;
int c = 0 ;
int vertpairs = 0;

 for (r = 0; r < ROW ; r++)
 {
     for (c = 0; c < COLUMN -1; c++)
     {
       {
       if(randchar_array[r][c] == randchar_array[r+1][c])
         vertpairs++;
       }
     }
  }

  return (vertpairs);
}

我的问题是：-1必要的第二个for语句为（C = 0;℃下COLUMN -1; C ++）。

My question is: Is the -1 necessary for the 2nd for statement " for (c = 0; c < COLUMN -1; c++)."

推荐答案

没有，从code（其中垂直比）似乎 - 1 应在外环代替

No, from the code (which compares vertically) it seems the - 1 should be on the outer loop instead.

现在它将比较在 randchar_array [ROW - 1 + 1]。[C] 这是出界，并给出了不确定的行为

Now it will compare at randchar_array[ROW - 1 + 1][c] which is out of bounds, and gives undefined behavior.

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