请问C支持范围解析？ [英] Does C supports scope resolution?

问题描述

    #include <stdio.h>

/* global variable declaration */
int g = 20;

int main ()
{
  /* local variable declaration */
  int g = 10;

  printf ("value of g = %d  %d\n",  g,::g);

  return 0;
}

当我试图运行此程序。它抛出误差的main.c：11：39：错误：预期前$ P $之前pssion'：'令牌
   的printf（G值=％D \\ N，G :: G）; 。但如果是用C ++编写，它工作正常。

When i am trying to run this program. It is throwing error main.c:11:39: error: expected expression before ':' token printf ("value of g = %d %d\n", g,::g);. But if it is written in C++, it works fine.

推荐答案

没有，这是一个C ++的功能。在C中，在内部范围内声明一个变量，将隐藏一个在外部范围。

No, that's a C++ feature. In C, declaring a variable in an inner scope will hide the one in the outer scope.

如果您的必须的做到这一点，你可以用指针来获得在外部范围，但它是一个有点杂牌的，这也不是我建议：

If you must do it, you can use pointers to get at the outer scope but it's a bit of a kludge and not something I'd recommend:

#include <stdio.h>
int g = 20;
int main () {
  int *pGlobalG = &g;
  int g = 10;
  printf ("value of g = %d %d\n", g, *pGlobalG);
  return 0;
}

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