浮点转换为字符串，而不sprintf的（） [英] Convert float to string without sprintf()

问题描述

我在编码一个基于微控制器的应用程序，我需要一个浮动转换为字符串，但我并不需要的sprintf相关的重开销（ ）。是否有任何雄辩的方式来做到这一点？我不需要太多。我只需要2位precision的。

I'm coding for a microcontroller-based application and I need to convert a float to a character string, but I do not need the heavy overhead associated with sprintf(). Is there any eloquent way to do this? I don't need too much. I only need 2 digits of precision.

推荐答案

试试这个。它应该是美好而小型的。我已经输出字符串直接 - 做一个printf，而不是sprintf的。我会离开它你为返回的字符串分配空间，以及作为结果复制到它。

Try this. It should be nice and small. I've output the string directly - doing a printf, rather than a sprintf. I'll leave it to you to allocate space for the return string, as well as copying the result into it.

// prints a number with 2 digits following the decimal place
// creates the string backwards, before printing it character-by-character from
// the end to the start
//
// Usage: myPrintf(270.458)
//  Output: 270.45
void myPrintf(float fVal)
{
    char result[100];
    int dVal, dec, i;

    fVal += 0.005;   // added after a comment from Matt McNabb, see below.

    dVal = fVal;
    dec = (int)(fVal * 100) % 100;

    memset(result, 0, 100);
    result[0] = (dec % 10) + '0';
    result[1] = (dec / 10) + '0';
    result[2] = '.';

    i = 3;
    while (dVal > 0)
    {
        result[i] = (dVal % 10) + '0';
        dVal /= 10;
        i++;
    }

    for (i=strlen(result)-1; i>=0; i--)
        putc(result[i], stdout);
}

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