获取屏幕位置从世界排名 [英] Get Screen Position From World Position

问题描述

我想从世界排名在DirectX屏幕位置。

I want to get Screen Position from World Position in DirectX.

我可以让我的球的世界上的地位。但我不知道我怎样才能将其转换为屏幕上的位置。

I can get my ball's world position. But I can't know how can I convert it to screen position.

推荐答案

您有一个观点/眼变换V（就是那个地方你的相机）和投影变换P上。

You have a view/eye transform V (the one that "places" your "camera") and a projection transform P.

裁剪空间坐标由

clip_position = P * V * world_space_position

从剪辑的空间，您通过将夹子空间达到NDC空间在第四次剪裁空间坐标W，即坐标。

From clip space you reach NDC space by dividing the clip space coordinates by the 4th clip space coordinate w, i.e.

ndc_x = clip_x / clip_w
ndc_y = clip_y / clip_w
ndc_z = clip_z / clip_w
ndc_w = clip_w / clip_w = 1

视口XY坐标，然后通过映射的范围为[-1,1]视口的尺寸达到了。 OpenGL和DirectX之间的差别是，在OpenGL深度范围[-1,1]映射到[0，DEPTH_BUFFER_RESOLUTION]，而在DirectX它的深度范围[0，1]映射到深度缓冲器值范围。

The viewport XY coordinates are then reached by mapping the range [-1,1] to the viewport dimensions. The difference between OpenGL and DirectX is, that in OpenGL the depth range [-1,1] is mapped to [0, DEPTH_BUFFER_RESOLUTION], while in DirectX it's the depth range [0, 1] that maps to the depth buffer value range.

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