数组和strpbrk用C [英] Arrays and strpbrk in C

问题描述

如果我的数组是：

char* String_Buffer = "Hi my name is <&1> and i have <&2> years old."
char* pos = strpbrk(String_buffer, "<");

现在pos是：

＆LT;＆功放; 1>和我有＆LT;＆安培; 2>岁的

" <&1> and i have <&2> years old. "

但我需要我的名字是。如何才能做到这一点？

But i need "Hi my name is". How can do this?

推荐答案

如果您跟踪启动分开，可以通过切出缓冲区的部分：

If you track start separately, you can "cut out" a section of the buffer:

char *start = String_Buffer;
char *end = strpbrk(String_Buffer, "<");

if (end) {
    /* found it, allocate enough space for it and NUL */
    char *match = malloc(end - start + 1);

    /* copy and NUL terminate */
    strncpy(match, start, end - start);
    match[end - start] = '\0';

    printf("Previous tokens: %s\n", match);
    free(match);
} else {
    /* no match */
}

要走路缓冲打印每个令牌，你只需吊成一个圈这样的：

To walk the buffer printing each token, you'll simply hoist this into a loop:

char *start = String_Buffer, *end, *match;

while (start) {
    end = strpbrk(start, "<");
    if (!end) {
        printf("Last tokens: %s\n", start);
        break;
    } else if (end - start) {
        match = malloc(end - start + 1);

        /* copy and NUL terminate */
        strncpy(match, start, end - start);
        match[end - start] = '\0';

        printf("Tokens: %s\n", match);
        free(match);

        end++; /* walk past < */
    }

    /* Walk to > */
    start = strpbrk(end, ">");
    if (start) {
        match = malloc(start - end + 1); /* start > end */
        strncpy(match, end, start - end);
        match[start - end] = '\0';

        printf("Bracketed expression: %s\n", match);
        free(match);
        start++; /* walk past > */
    }
}

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