如何字符串存储到在一个结构中声明的字符指针 [英] How to store a character string into a character pointer declared in a structure

问题描述

这是我的code：

 #include<stdio.h>



    struct p{

           char* d;
           };

    typedef struct p* pt;

    int main(){
        pt opt;
        opt=(pt)malloc(sizeof(struct p));

        scanf("%s",(opt->d));


        printf("%s",opt->d);



        getch();

        return 0;

        }

每次我运行它，它接受并打印字符串不错，但出现错误。
在调试它告诉，有一个段错误，但不指向它在哪里？
到底哪里出问题了，它似乎是相当正确的。

Everytime I run it , it accepts and prints the string fine but an error occur. On debugging it tells that there is a segmentation fault but doesn't points to where it is? What is going wrong , It's seems to be fairly correct.

推荐答案

scanf函数把扫描的字符串到字符缓冲区。但在你的code你的字符指针没有指向它应该指向一个缓冲区中的所有事情

the scanf put the scanned string to a char buffer. but in your code your char pointer is not pointing to any thing it should be pointed to a buffer

如果您的gcc> 2.7，可以使用MS％。这将允许scanf函数为指针分配内存

If your gcc> 2.7, you can use "%ms". this will allow to scanf to allocate memory for your pointer

scanf("%ms",(opt->d));

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