如何获得照相机从滚动，俯仰和偏航矢量？ [英] How to get camera up vector from roll, pitch, and yaw?

问题描述

我需要从一个滚动，俯仰和偏航角度得到了载体一个摄像头（以获得正确的期待）（度）。我一直在尝试不同的事情了几个小时，没有运气:(。任何帮助这里将是AP preciated！

I need to get an up vector for a camera (to get the right look) from a roll, pitch, and yaw angles (in degrees). I've been trying different things for a couple hours and have had no luck :(. Any help here would be appreciated!

推荐答案

滚动，俯仰和偏航定义3轴的旋转。从这些角度可以构造一个3x3变换矩阵EX preSS这种旋转（这里看看）
之后，你有这个矩阵你把你的定期向上向量，说（0,1,0），如果上为Y轴，并与矩阵相乘。您将获得的是转化了载体。

Roll, Pitch and Yaw define a rotation in 3 axis. from these angles you can construct a 3x3 transformation matrix which express this rotation (see here how)
After you have this matrix you take your regular up vector, say (0,1,0) if 'up' is the Y axis and multiply it with the matrix. What you'll get is the transformed up vector.

修改 -
应用转换到（0,1,0）是同样的事情，走的是中间一排。 3矩阵的行组成的旋转系统的正交基。你要知道，一个3D图形API使用4X4矩阵。因此，为了使一个4x4矩阵出了3×3的旋转矩阵，你需要添加一个'1'M [3] [3]（角落）和零点在剩下的像这样：

Edit-
Applying the transformation to (0,1,0) is the same thing as taking the middle row. The 3 rows of the matrix make up an orthogonal base of the rotated system. Mind you that a 3D graphic API uses 4x4 matrices. So to make a 4x4 matrix out of the 3x3 rotation matrix you need to add a '1' at M[3][3] (the corner) and zeros at the rest like so:

r r r 0
r r r 0 
r r r 0
0 0 0 1

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