％（MOD）的说明 [英] % (mod) explanation

问题描述

今天，我写在C＃中的程序，我用的％以计算某些指标......我的计划我以前不工作，所以我debuged它，我意识到，％工作不象其他程序语言，我知道

Today I was writing an program in C# and I used % to calculate some index... my program did't work so I debuged it and I realized that "%" is not working like in other program languages that I know.

例如：

在蟒蛇％的回报值是这样的：

in python % returns values like this:

for x in xrange (-5, 6):
     print x, "% 5 =", x % 5

-5 % 5 = 0
-4 % 5 = 1
-3 % 5 = 2
-2 % 5 = 3
-1 % 5 = 4
0 % 5 = 0
1 % 5 = 1
2 % 5 = 2
3 % 5 = 3
4 % 5 = 4
5 % 5 = 0

在C＃中：

for (int i = -5; i < 6; i++)
{
    Console.WriteLine(i + " % 5 = " + i % 5);
}

-5 % 5 = 0
-4 % 5 = -4
-3 % 5 = -3
-2 % 5 = -2
-1 % 5 = -1
0 % 5 = 0
1 % 5 = 1
2 % 5 = 2
3 % 5 = 3
4 % 5 = 4
5 % 5 = 0

我的问题是：

难道我做错了什么或％不能正常工作像它应注意什么？

Did I done something wrong or % is not working like it should?

推荐答案

由于在评论中解释的那样，不同的行为是由设计。不同的语言只是归于不同的含义在％运营商

As explained in the comments, the different behaviour is by design. The different languages just ascribe different meanings to the % operator.

您问：

我如何使用模运算在C＃？

How can I use modulus operator in C#?

您可以定义一个模运算符自己的行为同样是为Python的％运营商：

You can define a modulus operator yourself that behaves the same was as the Python % operator:

int mod(int a, int n)
{
    int result = a % n;
    if ((a<0 && n>0) || (a>0 && n<0))
        result += n;
    return result;
}

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