彩色规模的基础上定制的范围是多少？十六进制？ [英] Colour scale based on custom range? in HEX?

问题描述

如何在十六进制创建一个自定义色阶理想？说由黄变红，这取决于一个对象的高度？这是实现这一正确的方式还是有，而无需将其转换在最后一个更好的方法：

 变种R：INT = 255;
变种B：INT = 0;
VAR了maxHeight：INT = 52;
VAR了minHeight：INT = 21;

VAR规模：INT = 255 /（了maxHeight-了minHeight）;

VAR G：INT = 255  - （（object.height-了minHeight）*等级）;

VAR hexColor：UINT = RGBtoHEX（R，G，B）;
 

---

 私有函数RGBtoHEX（R：INT，G：INT，B：INT）：UINT
{
返回为r＆LT; 16 | G＆LT;＆LT; 8 | B：
}
 

解决方案

下面是一个可以让你找到两个人基于一系列的0-1之间的颜色值。我认为这将满足您的需求。

 私有函数getBetweenColourByPercent（价值：数= 0.5 / * 0-1 * /，增强色：UINT = 0XFFFFFF，low​​Color：UINT = 0x000000处）：UINT {
    变种R：UINT =增强色＆GT;＆GT; 16;
    VAR G：UINT =增强色＆GT;＆GT; 8安培; 0xFF的;
    变种B：UINT =增强色和放大器; 0xFF的;

    R + =（（lowColor＆GT;＆GT; 16） -  R）*值;
    克+ =（（lowColor＆GT;→8＆安培;为0xFF） - 克）*值;
    B + =（（lowColor＆安培; 0xFF的） -  B）*值;

    返回（R＆LT;＆LT; 16 | G＆LT;＆LT; 8 | B）;
}
 

How do I create a custom colour scale ideally in Hex? say from yellow to red, depending on the height of an object? is this a correct way to achieve this or is there a better way without having to convert it at the end?:

var r:int = 255;
var b:int = 0;
var maxHeight:int = 52;
var minHeight:int = 21;

var scale:int = 255 / (maxHeight-minHeight);

var g:int = 255 - ((object.height-minHeight) * scale);

var hexColor:uint = RGBtoHEX(r,g,b);

---

private function RGBtoHEX(r:int, g:int, b:int) :uint
{
return r << 16 | g << 8 | b;
}

解决方案

Here is a function that allows you to find a colour value between two others based on a range of 0-1. I think it will meet your needs

private function getBetweenColourByPercent(value:Number = 0.5 /* 0-1 */, highColor:uint = 0xFFFFFF, lowColor:uint = 0x000000):uint {
    var r:uint = highColor >> 16;
    var g:uint = highColor >> 8 & 0xFF;
    var b:uint = highColor & 0xFF;

    r += ((lowColor >> 16) - r) * value;
    g += ((lowColor >> 8 & 0xFF) - g) * value;
    b += ((lowColor & 0xFF) - b) * value;

    return (r << 16 | g << 8 | b);
}

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