使用正则表达式，直到达到一个子匹配任何字符？ [英] Using regex to match any character until a substring is reached?

问题描述

我希望能够匹配字符的特定序列，从一个特定的字符串，并与特定的字符串结尾。我正向前查找正则表达式的作品，如果只有一个实例来匹配一条线，但如果应该有一行多个匹配。我明白这是因为（+）捕获了一切，直到的最后的阳性表达前瞻找到。它会是不错的，如果它能够捕捉一切，直到的第一个的表达被发现

I'd like to be able to match a specific sequence of characters, starting with a particular substring and ending with a particular substring. My positive lookahead regex works if there is only one instance to match on a line, but not if there should be multiple matches on a line. I understand this is because (.+) captures up everything until the last positive lookahead expression is found. It'd be nice if it would capture everything until the first expression is found.

下面是我的正则表达式的尝试：

Here is my regex attempt:

@@FOO\[(.*)(?=~~)~~(.*)(?=\]@@)\]@@

样品输入：

@@FOO[abc~~hi]@@    @@FOO[def~~hey]@@

所需的输出：2场比赛，2匹配组，每组（ABC，喜）和（闪避，嘿嘿）

Desired output: 2 matches, with 2 matching groups each (abc, hi) and (def, hey).

实际输出：1场2组（ABC ~~喜] @@ @@ FOO [闪避，嘿嘿）

Actual output: 1 match with 2 groups (abc~~hi]@@ @@FOO[def, hey)

有没有办法来获得所需的输出

Is there a way to get the desired output?

在此先感谢！

推荐答案

使用问号，它会比赛的几次越好。

Use the question mark, it will match as few times as possible.

@@FOO\[(.*?)(?=~~)~~(.*?)(?=\]@@)\]@@

这一次也适用，但没有那么严格，虽然更容易阅读

This one also works but is not as strict although easier to read

@@FOO\[(.*?)~~(.*?)\]@@

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