是size_t总是unsigned？ [英] is size_t always unsigned?

问题描述

标题：size_t总是无符号，即 size_t x 是 x 总是> = 0 ？

As title: is size_t always unsigned, i.e. for size_t x, is x always >= 0 ?

推荐答案

是。通常定义为类似以下内容（在32位系统上）：

Yes. It's usually defined as something like the following (on 32-bit systems):

typedef unsigned int size_t;

参考：

在C标准中定义 size_t 在< cstddef> 中< stddef .h> 。

C标准节4.1.5将 size_t 定义为 sizeof 运算符

C++ Standard Section 18.1 defines size_t is in <cstddef> which is described in C Standard as <stddef.h>.
C Standard Section 4.1.5 defines size_t as an unsigned integral type of the result of the sizeof operator

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