用户输入整数 - 错误处理 [英] User Input of Integers - Error Handling

问题描述

我对我的程序的某些输入区域有些麻烦。有几个部分，用户输入特定的整数。即使他们输入错误的，这是所有罚款和dandy，但我注意到，如果他们输入任何非整数类型，如'm'，那么它会循环错误消息重复。

我有一些功能，它们有整数输入。下面是一个例子。

  void Room :: move（vector< Room>& v，int exone，int extwo， int exthree，int current）
 {
v [current] .is_occupied = false; 
 int room_choice; 
 cout<< \\\
输入房间移动到：; 
 while（true）
 {
 cin>>房间
 if（room_choice == exone || room_choice == extwo || room_choice == exthree）
 {
 v [room_choice] .is_occupied = true; 
 break; 
} 
 else cout<< 输入不正确，请重试：; 
} 
} 
  

[已解决]

  void Room :: move（vector< Room>& v，int exone，int extwo，int exthree，int current）
 {
v [current] .is_occupied = false; 
 int room_choice; 
 cout<< \\\
输入房间移动到：; 
 while（true）
 {
 cin>>房间
 if（room_choice == exone || room_choice == epwo || room_choice == exthree）
 {
 v [room_choice] .is_occupied = true; 
 break; 
} 
 else if（cin.fail（））
 {
 cin.clear（）
 cin.ignore（）
 cout< 输入不正确，请重试：; 
} 
} 
} 
  

解决方案>

您可以使用 cin.good（）或 cin.fail（）处理提供的输入值。然后，如有必要，您可以使用 cin.clear（）清除错误状态，然后再继续处理。

I'm having some trouble with certain input areas of my program. There are a few parts where the user inputs a specific integer. Even if they enter the wrong one that's all fine and dandy, but I noticed if they enter anything not of integer type like 'm' then it will loop the error message repeatedly.

I have a couple functions that have integer input in them. Here's one for an example.

void Room::move(vector<Room>& v, int exone, int extwo, int exthree, int current)
{
    v[current].is_occupied = false;
    int room_choice;
    cout << "\nEnter room to move to: ";
    while(true)
    {
        cin >> room_choice;
        if(room_choice == exone || room_choice == extwo || room_choice == exthree)
        {
            v[room_choice].is_occupied = true;
            break;
        }
        else cout << "Incorrect entry. Try again: ";
    }
}

[SOLVED]

void Room::move(vector<Room>& v, int exone, int extwo, int exthree, int current)
{
    v[current].is_occupied = false;
    int room_choice;
    cout << "\nEnter room to move to: ";
    while(true)
    {
        cin >> room_choice;
        if(room_choice == exone || room_choice == extwo || room_choice == exthree)
        {
            v[room_choice].is_occupied = true;
            break;
        }
        else if(cin.fail())
        {
          cin.clear()
          cin.ignore()
          cout << "Incorrect entry. Try again: ";
        }
    }
}

解决方案

You can use cin.good() or cin.fail() to determine whether cin could successfully deal with the input value provided. You can then use cin.clear(), if necessary, to clear the error state before continuing processing.

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