如何轻松地检测2个ROIs是否相交在OpenCv？ [英] How can one easily detect whether 2 ROIs intersects in OpenCv?

问题描述

我试图检测2个感兴趣区域（ CvRect s）是否在OpenCV中相互交叉。我可以明显地手动键入几个（或相当多的）条件进行检查，但这不会是一个很好的方法来做它（imo）。

任何人都可以向我推荐其他解决方案？在OpenCV中有一个准备好的方法吗？

解决方案

我不知道任何现成的解决方案的C接口（ CvRect ），但是如果你使用C ++方法（ cv :: Rect ），你可以很容易地说

  interesect = r1& r2;     /basic_structures.html?highlight=rect#Rect_\">完整列表的矩形操作是
  //在除了类成员，在矩形上实现以下操作
 //：
 
 //（将矩形移动一定偏移量）
 //（扩展或缩小矩形一定量）
 rect + = point，rect  -  = point，rect + = size，rect  -  = size（augmenting operations）
 rect = rect1& rect2（rectangle intersection）
 rect = rect1 | rect2（rect2和rect3的最小矩形区域）
 rect& = rect1，rect | = rect1（以及相应的扩展操作）
 rect == rect1，rect！= rect1 $ b  
 
I am trying to detect whether 2 Regions of Interest (CvRects) are intersecting one another in OpenCV. I can obviously manually type several (or rather a lot of) conditions to be checked but that wouldn't really be a good way to do it (imo). 

Can anyone suggest me any other solution? Is there a ready method in OpenCV for that ? 
解决方案
I do not know of any ready-made solution for the C interface (CvRect), but if you use the C++ way (cv::Rect), you can  easily say 
interesect  = r1 & r2;
The complete list of operations on rectangles is
// In addition to the class members, the following operations 
// on rectangles are implemented:

// (shifting a rectangle by a certain offset)
// (expanding or shrinking a rectangle by a certain amount)
rect += point, rect -= point, rect += size, rect -= size (augmenting operations)
rect = rect1 & rect2 (rectangle intersection)
rect = rect1 | rect2 (minimum area rectangle containing rect2 and rect3 )
rect &= rect1, rect |= rect1 (and the corresponding augmenting operations)
rect == rect1, rect != rect1 (rectangle comparison)


                        
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