什么是C ++中的SIGSEGV运行时错误？ [英] What is SIGSEGV run time error in C++?

问题描述

我需要知道分段错误的根本原因，也可以告诉我如何处理它。

I need to know the root cause of the segmentation fault, and also can anyone tell me how to handle it.

推荐答案

维基百科提供了答案以及其他一些来源。

Wikipedia has the answer, along with a number of other sources.

segfault基本上意味着你使用指针做了一些坏事。这可能是一个segfault：

A segfault basically means you did something bad with pointers. This is probably a segfault:

char *c = NULL;
...
*c; // dereferencing a NULL pointer

或者：

char *c = "Hello";
...
c[10] = 'z'; // out of bounds, or in this case, writing into read-only memory

char *c = new char[10];
...
delete [] c;
...
c[2] = 'z'; // accessing freed memory

相同的基本原则在每种情况下 -

Same basic principle in each case - you're doing something with memory that isn't yours.

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