C ++中的删除如何知道要删除多少内存位置 [英] How does the delete in C++ know how many memory locations to delete

问题描述

删除操作如何工作？是更好然后free（）？如果u ptr = new char [10] ，那么使用 delete ptr

$ <$>

只有 delete code> free 仅作为函数存在。在C ++下，鼓励使用 new / delete over malloc c $ c> / free（）。

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删除操作符中的内部魔术。当使用 new [] 创建数组时，数组的大小存储在内存块的元数据中。 delete [] 使用该信息。

这些当然是编译器，和实现依赖。

how does the delete operator work? Is it better then free()?. Also if u do ptr=new char[10], then delete using delete ptr, how does the pointer know how many locations to delete.

解决方案

There is only delete operator, free exist only as function. Under C++, you are encouraged to use new/delete over malloc()/free().

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There is an internal "magic" in delete operator. When an array is created with new[], the size of array is stored in the metadata at the memory block. delete[] makes use of that information.

All this is of course compiler-, OS-, optimizer- and implementation-dependent.

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