两个字符串文字具有相同的指针值？ [英] Two string literals have the same pointer value?

问题描述

当我使用MinGW运行此程序时，输出为=

 ＃include< iostream> 
 
 using namespace std; 
 
 int main（）
 {
 char * str1 =Hello; 
 char * str2 =Hello; 
 
 if（str1 == str2）
 cout<<=; 
 else 
 cout<<！=; 
 
 
 return 0;但是，在逻辑上，它应该是！=，coz这些都是指针和他们指向不同的存储器位置。当我在我的Turbo C ++中运行这个代码时，我得到了！= 
解决方案
然而，它们是否指向不同的位置取决于实现。对于编译器只存储一次字符串字面值并在代码中使用它的地址，它是完全有效的。
 
When I run this program using MinGW, im getting output as "="
#include<iostream>

using namespace std;

int main()
{
 char *str1 = "Hello";
 char *str2 = "Hello";

 if(str1==str2)
 cout<<"=";
 else
 cout<<"!=";


 return 0;
}
However, logically, it should be !=, coz these are pointers and they are pointing to different memory locations. When I run this code in my Turbo C++, i get !=
解决方案
You are right in that they are pointers. However, whether they are pointing to different locations or not depends on the implementation. It is perfectly valid for a compiler to store a string literal just once and use its address wherever it's used in code.

                        
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