如何传递一个类方法作为另一个函数的参数在C ++和OpenGL? [英] How to pass a class method as an argument for another function in C++ and openGL?
问题描述
我知道这个事情是有效的:
I know this thing works:
void myDisplay()
{
...
}
int main()
{
...
glutDisplayFunc(myDisplay)
...
}
所以我试图将myDisplay()函数包含在一个类中。因为我想在将来用不同的类重载它。但是,编译器抱怨说,类型为'void(ClassBlah ::)()'的参数不匹配'void(*)()'的参数,
so I tried to include myDisplay() function to a class that I made. Because I want to overload it in the future with a different class. However, the compiler complains that
'。
这是我尝试做的:
class ClassBlah
{
....
void myDisplay()
....
}
......
int main()
{
...
ClassBlah blah
glutDisplayFunc(blah.myDisplay)
...
}
有人知道如何解决这个问题吗?非常感谢。
Does anybody knows how to fix this problem? Many thanks.
推荐答案
首先,在非静态成员函数中有一个隐含的this指针,将 ClassBlah
中的 void myDisplay()
更改为静态。解决这个限制是很尴尬的,这就是为什么C ++ faq lite说不要这样做
Firstly, there is an implicit "this" pointer in non-static member functions, so you'll need to change your void myDisplay()
in ClassBlah
to be static. It's awkward to work around this limitation, which is why the C++ faq lite says don't do it
然后,您应该能够传递 ClassBlah :: myDisplay
。
Then, you should be able to pass the functions as ClassBlah::myDisplay
.
根据您的重载动机(例如,您是否要在运行时或在编译时间执行热交换实现),您可以考虑使用实用程序handler静态类,它包含一个指向你的基类的指针,并通过该类指定责任。
Depending on your motivation for overloading (ie are you going to hotswap implementations in and out at runtime, or only at compile time?) you might consider a utility "handler" static class that contains a pointer to your base class, and delegates responsibility through that.
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