跳过期望的字符，如scanf（）with cin [英] Skipping expected characters like scanf() with cin

问题描述

如何实现 scanf（％d＃％d，& a，& b）; / code>

How to achieve scanf("%d # %d",&a,&b);sort of effect with cin in C++ ?

推荐答案

您可以创建自己的流操纵器。这很容易。

You could create your own stream manipulator. It is fairly easy.

#include <ios>
#include <iostream>
using namespace std;

struct skip
{
    const char * text;
    skip(const char * text) : text(text) {}
};

std::istream & operator >> (std::istream & stream, const skip & x)
{
    ios_base::fmtflags f = stream.flags();
    stream >> noskipws;

    char c;
    const char * text = x.text;
    while (stream && *text++)
        stream >> c;

    stream.flags(f);
    return stream;
}

int main()
{
    int a, b;
    cin >> a >> skip(" # ") >> b;
    cout << a << ", " << b << endl;
    return 0;
}

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