在向量< double>上使用std :: max_element [英] Using std::max_element on a vector<double>

问题描述

我试图使用 std :: min_element 和 std :: max_element 返回最小和最大在向量中的元素。我的编译器不喜欢我目前正试图使用​​它们，我不明白错误消息。我当然可以写我自己的程序来找到最小/最大值，但我想了解如何使用这些函数。

I'm trying to use std::min_element and std::max_element to return the min and max elements in a vector of doubles. My compiler doesn't like how I'm currently trying to use them, and I don't understand the error message. I could of course write my own procedure to find the min/max, but I'd like to understand how to use the functions.

#include <vector>
#include <algorithm>

using namespace std;

int main(int argc, char** argv) {

    double cLower, cUpper;
    vector<double> C;

    // code to insert values in C not shown here

    cLower = min_element(C.begin(), C.end());
    cUpper = max_element(C.begin(), C.end());

    return 0;
}

这里是编译器错误：

../MIXD.cpp:84: error: cannot convert '__gnu_cxx::__normal_iterator<double*, std::vector<double, std::allocator<double> > >' to 'double' in assignment
../MIXD.cpp:85: error: cannot convert '__gnu_cxx::__normal_iterator<double*, std::vector<double, std::allocator<double> > >' to 'double' in assignment

有人请解释我做错了什么？ / p>

Would someone please explain what I'm doing wrong?

推荐答案

min_element 和 max_element 返回迭代器，而不是值。所以你需要 * min_element ... 和 * max_element ... 。

min_element and max_element return iterators, not values. So you need *min_element... and *max_element....

这篇关于在向量< double>上使用std :: max_element的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！