将const char *转换为向量< double>更好的方法 [英] converting const char* to vector<double> better way

问题描述

我通过UDP接收 const char * 。此文本的大小不同（即不是固定大小）。此文本的值为double类型。我想将它转换为 vector< double> 。这是我做的。

I'm receiving const char* via UDP. The size of this text varies (i.e. not fixed size). This text has values of double type. I want to convert it to vector<double>. This what I've done.

std::vector<double> convertToDoubVect(const char * buff)
{
    std::vector<double> vec;
    std::istringstream data(buff);

    int i = 0, count = 0;

    // get number of doubles in const char* by incrementing count
    while( buff[i] != '\0' )
    {
        if ( buff[i] == ' ')
            ++count;
        ++i;
    }

    // allocate an array for the total doubles
    double *n = new double[count+1];

    // convert const char* to vector<double>
    for ( int i(0); i <= count; ++i)
    {
        data >> n[i];
        vec.push_back(n[i]);
    }

    delete n;

    return vec;
}

int main()
{

    const char *doubStr = "2.3 4.3 5.6 2.1 4.4 3.1";
    std::vector<double> vec = convertToDoubVect(doubStr);

    for ( int i(0); i < vec.size(); ++i)
    {
        std::cout << vec[i] << std::endl;
    }

    return 0;
}

这绝对不是一个优雅的方式，有什么建议么！我正在使用visual studio 2010.

This is definitely not an elegant way but it did the trick. Any suggestions! I'm using visual studio 2010.

推荐答案

#include <sstream>
#include <vector>
#include <iterator>

const char* doubStr = "2.3 4.3 5.6 2.1 4.4 3.1";
std::istringstream iss(doubStr);
std::istream_iterator<double> it(iss), end;
std::vector<double> v(it, end);

演示。

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