C ++中的静态方法 [英] Static methods in C++
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问题描述
我在使用C ++中的静态方法时遇到一些麻烦
示例.h:
class IC_Utility {
public:
IC_Utility();
〜IC_Utility();
std :: string CP_PStringToString(const unsigned char * outString);
void CP_StringToPString(std :: string& inString,unsigned char * outString,short inMaxLength);
static void CP_StringToPString(std :: string& inString,unsigned char * outString);
void CP_StringToPString(FxString& inString,FxUChar * outString);
};
示例.cpp:
static void IC_Utility :: CP_StringToPString(std :: string& inString,unsigned char * outString)
{
short length = inString.length
if(outString!= NULL)
{
if(length> = 1)
CPLAT :: CP_Utility :: CP_CopyMemory(inString.c_str & outString [1],length);
outString [0] = length;
}
}
我想打一个电话:
IC_Utility :: CP_StringToPString(directoryNameString,directoryName);
但我得到一个错误:
错误:无法声明成员函数'static void IC_Utility :: CP_StringToPString(std :: string& unsigned char *)'以具有静态链接
/ pre>
我不明白为什么我不能这样做。
解决方案删除
static
方法定义中的关键字。
static
关键字放在.cpp文件中意味着某个函数有一个静态连接,即。它只能从同一文件中的其他函数访问。I am having a little trouble working with static methods in C++
Example .h:
class IC_Utility { public: IC_Utility(); ~IC_Utility(); std::string CP_PStringToString( const unsigned char *outString ); void CP_StringToPString( std::string& inString, unsigned char *outString, short inMaxLength ); static void CP_StringToPString( std::string& inString, unsigned char *outString); void CP_StringToPString( FxString& inString, FxUChar *outString); };
Example .cpp:
static void IC_Utility::CP_StringToPString(std::string& inString, unsigned char *outString) { short length = inString.length(); if( outString != NULL ) { if( length >= 1 ) CPLAT::CP_Utility::CP_CopyMemory( inString.c_str(), &outString[ 1 ], length ); outString[ 0 ] = length; } }
I wanted to make a call like:
IC_Utility::CP_StringToPString(directoryNameString, directoryName );
But I get an error:
error: cannot declare member function 'static void IC_Utility::CP_StringToPString(std::string&, unsigned char*)' to have static linkage
I dont understand why I cannot do this. Can anyone help me understand why and how to achieve what I want?
解决方案Remove
static
keyword in method definition. Keep it just in your class definition.
static
keyword placed in .cpp file means that a certain function has a static linkage, ie. it is accessible only from other functions in the same file.这篇关于C ++中的静态方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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