复制具有引用类型的成员变量的C ++类 [英] Copying a C++ class with a member variable of reference type

问题描述

我有一个类存储对其父的引用，引用在构造函数中传递。如果我试图复制一个实例，我得到一个错误错误C2582：'操作符='函数不可用推测到参考是不可分配的。

I've a class which stores a reference to its parent, the reference is passed in the constructor. If I try to copy an instance I get an error "error C2582: 'operator =' function is unavailable" presumably down to the reference being non-assignable.

例如（过度简化但我认为有关键点）：

e.g (over-simplified but I think has the key points):

class MyClass
{
public:
 MyClass(OtherClass &parent) : parent(parent) {}
private:
 OtherClass &parent;
};

MyClass obj(*this);
.
.
.
obj = MyClass(*this);

推荐答案

是的，如果您需要支持分配指针而不是引用几乎是你唯一的选择。

Yes, if you need to support assignment, making it a pointer instead of a reference is nearly your only choice.

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