如何将鼠标在屏幕上的坐标转换为3D坐标 [英] How to convert mouse coordinate on screen to 3D coordinate

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问题描述

我在C ++中使用GLUT创建了一个3D应用程序。

I'm creating a 3D application using GLUT in C++.

现在,我想实现一个类似下面的方法:

Now, I want to implement a method similar to this:

Vector3 * MyClass :: get3DObjectfromMouse(int mouseX,int mouseY);

我可以实现这个方法吗?

How can I implement this method?

推荐答案

因为它被 Andon M. Coleman ,一种方法可以实现这一点是通过做一个射线/与未投影的屏幕坐标交叉测试。此技术通常称为挑选

As it was commented by Andon M. Coleman, one way you can achieve this is by doing a ray/object intersection test, with unprojected screen coordinates. This technique is commonly known as picking.

假设我们有一个3D对象类型/类: p>

Assume we have a 3D object type/class:

class Object3D { ... };

3D拾取函数将返回所有对象的列表, 2D点到近平面中的同一点。

A 3D picking function would return a list of all objects that are intersected by a line going from the given 2D point in the near plane to the same point in the far plane.

struct LineSegment 
{
    Vector3 start;
    Vector3 end;
};

Object3D[] Pick(float x, float y)
{
    LineSegment lineSeg;
    Object3D[] intersectedObjs;

    // Do both un-projections for z-near (0) and z-far (1).
    // This produces a line segment going from z-near to far.
    UnProject(x, y, /* z = */ 0.0, modelViewMatrix, projectionMatrix, viewport, lineSeg.start);
    UnProject(x, y, /* z = */ 1.0, modelViewMatrix, projectionMatrix, viewport, lineSeg.end);

    // Iterate all object in the scene or in the current view:
    for (Object3D obj : scene)
    {
        if (TestLineIntersection(obj, lineSeg))
        {
            // This object is crossed by the picking line.
            intersectedObjs.Add(obj);
        }
    }

    // Optionally you might want sort them from distance 
    // to the camera/viewer before returning the intersections.
    return intersectedObjs;
}

并且 UnProject() function看起来像这样:

And the UnProject() function would look like this:

bool UnProject(float winX, float winY, float winZ,
               const Matrix4 & modelView, const Matrix4 & projection,
               const ScreenRect viewport, Vector3 & worldCoordinates)
{
    // Compute (projection x modelView) ^ -1:
    const Matrix4 m = inverse(projection * modelView);

    // Need to invert Y since screen Y-origin point down,
    // while 3D Y-origin points up (this is an OpenGL only requirement):
    winY = viewport.Height() - winY;

    // Transformation of normalized coordinates between -1 and 1:
    Vector4 in;
    in[0] = (winX - viewport.X()) / viewport.Width()  * 2.0 - 1.0;
    in[1] = (winY - viewport.Y()) / viewport.Height() * 2.0 - 1.0;
    in[2] = 2.0 * winZ - 1.0;
    in[3] = 1.0;

    // To world coordinates:
    Vector4 out(m * in);
    if (out[3] == 0.0) // Avoid a division by zero
    {
        worldCoordinates = Vector3Zero;
        return false;
    }

    out[3] = 1.0 / out[3];
    worldCoordinates[0] = out[0] * out[3];
    worldCoordinates[1] = out[1] * out[3];
    worldCoordinates[2] = out[2] * out[3];
    return true;
}

要澄清, TestLineIntersection $ c>执行一行与 AABB 交叉点测试。边界框应该转换为世界空间,因为它通常表示为局部模型空间中的一组点。

To clarify, TestLineIntersection() does a line vs AABB intersection test. The bounding box should be transformed to world-space, since it is usually expressed as a set of points in local model-space.

bool TestLineIntersection(const Object3D & obj, const LineSegment & lineSeg)
{
    AABB aabb = obj.GetAABB();
    aabb.TransformBy(obj.modelMatrix);
    return aabb.LineIntersection(lineSeg.start, lineSeg.end);
}

// AABB.cpp:
bool AABB::LineIntersection(const Vector3 & start, const Vector3 & end) const
{
    const Vector3 center     = (mins + maxs) * 0.5;
    const Vector3 extents    = maxs - center;
    const Vector3 lineDir    = 0.5 * (end - start);
    const Vector3 lineCenter = start + lineDir;
    const Vector3 dir        = lineCenter - center;

    const float ld0 = Mathf::Abs(lineDir[0]);
    if (Mathf::Abs(dir[0]) > (extents[0] + ld0))
    {
        return false;
    }

    const float ld1 = Mathf::Abs(lineDir[1]);
    if (Mathf::Abs(dir[1]) > (extents[1] + ld1))
    {
        return false;
    }

    const float ld2 = Mathf::Abs(lineDir[2]);
    if (Mathf::Abs(dir[2]) > (extents[2] + ld2))
    {
        return false;
    }

    const Vector3 vCross = cross(lineDir, dir);
    if (Mathf::Abs(vCross[0]) > (extents[1] * ld2 + extents[2] * ld1))
    {
        return false;
    }
    if (Mathf::Abs(vCross[1]) > (extents[0] * ld2 + extents[2] * ld0))
    {
        return false;
    }
    if (Mathf::Abs(vCross[2]) > (extents[0] * ld1 + extents[1] * ld0))
    {
        return false;
    }

    return true;
}

这篇关于如何将鼠标在屏幕上的坐标转换为3D坐标的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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