函数式宏和奇怪的行为 [英] Function-like macros and strange behavior

问题描述

我已经开始阅读Effective C ++，在第2项中的某一点，提到以下内容：

I have started reading Effective C++ and at some point in item 2, the following is mentioned:

// call f with the maximum of a and b
#define CALL_WITH_MAX(a, b) f((a) > (b) ? (a) : (b))

...

int a = 5, b = 0;
CALL_WITH_MAX(++a, b); // a is incremented twice
CALL_WITH_MAX(++a, b+10); // a is incremented once

在调用f $ b之前递增b $ b取决于与什么进行比较！

Here, the number of times that a is incremented before calling f depends on what it is being compared with!

的确，如果我使用一个简单的打印语句在 f ，7在第一次调用打印，但我不能为我的生活找出为什么。我缺少明显的东西吗？

Indeed, if I use a simple print statement in f, 7 gets printed in the first call, but I cannot for the life of me figure out why. Am I missing something obvious?

推荐答案

编译器用逐字逐句替换宏的内容。所以你最终得到

The compiler replaces the macros with exactly what you pass in, verbatim. So you end up with

int a = 5, b = 0;
f((++a) > (b) ? (++a) : (b));
f((++a) > (b+10) ? (++a) : (b+10));

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