C ++ - 如何重载operator + =？ [英] C++ -- How to overload operator+=?
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问题描述
给定以下代码段
： class Num
{
public：
Num（int iNumber = 0）：m_iNumber（iNumber）{}
Num operator + =（const Num& rhs）
{
this-> m_iNumber =（this-> ; m_iNumber + rhs.m_iNumber）;
return * this;
}
private：
int m_iNumber;
};
// ======================================== ===================
int _tmain（int argc，_TCHAR * argv []）
{
Num a（10）;
Num b（100）;
b + = a;
return 0;
}
我想知道如何正确重载
- p>如何定义此运算符的签名？
-
如何实现函数体？
-
如何使用此重载运算符？
我提供了一个如上所述的解决方案，
解决方案
由参考返回会更好
Num& operator + =（const Num& rhs）{
this-> m_iNumber + = rhs.m_iNumber;
return * this;
}
Given the following code snippet,
class Num
{
public:
Num(int iNumber = 0) : m_iNumber(iNumber) {}
Num operator+=(const Num& rhs)
{
this->m_iNumber = (this->m_iNumber + rhs.m_iNumber);
return *this;
}
private:
int m_iNumber;
};
//===========================================================
int _tmain(int argc, _TCHAR* argv[])
{
Num a(10);
Num b(100);
b += a;
return 0;
}
I would like to know how to correctly overload the operator+=.
Questions:
How to define the signature of this operator? Specially, what should be used for the return value?
How to implement the function body?
How to use this overload operator?
I have provided a solution as above but I have concerns that it is not correct.
解决方案
Returning by reference would be better
Num& operator+=(const Num& rhs){
this->m_iNumber += rhs.m_iNumber;
return *this;
}
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