C ++全局重载operator = [英] C++ globally overloaded operator=

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本文介绍了C ++全局重载operator =的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述


可能重复:


您好,



我有以下代码...

  //头文件
struct dataRecord {
size_t id;
char name [gcNameLength];
};

void operator =(dataRecord& adr,const dataRecord& bdr);

编译时gcc给我出现以下错误。

 错误:'void operator =(dataRecord& const dataRecord&)'必须是非静态成员函数

感谢您的帮助。

解决方案

c $ c> = 操作

类似的操作:

  struct dataRecord {
size_t id;
char name [gcNameLength];
dataRecord& operator =(const dataRecord&){
//在这里写入重载代码
}
};


Possible Duplicate:
What does “operator = must be a non-static member” mean? (C++)

Hi,

I have the following code...

// Header file
  struct dataRecord{
     size_t id;
     char name[gcNameLength];
  };

  void operator=(dataRecord &adr, const dataRecord &bdr);

How ever gcc gives me the following error when compiling.

error: ‘void operator=(dataRecord&, const dataRecord&)’ must be a nonstatic member function

Thanks for the help.

解决方案

You need to overload = operation on the struct dataRecord itself.

Something like:

struct dataRecord{
   size_t id;
   char name[gcNameLength];
   dataRecord& operator= (const dataRecord&) {
       // write overload code here
   }
};

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