C ++ Tic Tac Toe游戏 [英] C++ Tic Tac Toe Game

问题描述

我很困惑。我试图创建一个tic tac toe游戏使用windows c ++视觉。到目前为止，我做得很好，直到我不断收到错误。我试图寻求帮助，但没有一个答案似乎是对的。这是我的实践问题。

I am so confused. I am trying to create a tic tac toe game using windows c++ visual. So far I was doing good until I kept getting errors. I tried looking for help but none of the answers seemed right. This is my practice problem.

1. 实施displayBoard以显示Tic Tac Toe板。



2. 提示用户在板上选择一个框，即1到9之间的数字，其中1是左上角。

1. Implement displayBoard to display Tic Tac Toe board.

2. Prompt User for a box on the board to select, i.e. a number between 1 and 9 with 1 being the upper left corner.

使用cin.get得到框号和isdigit来验证它是一个
号码;
1 | 2 | 3
4 | 5 | 6
7 | 8 | 9
如果盒子可用，在其中放置适当的X或O并切换播放器，即X变为O，反之亦然。
如果框不可用，警告用户并获得另一个框，直到他们选择有效的打开框。

use cin.get(box) to get the box number and isdigit to verify it is a number; 1 | 2 | 3 4 | 5 | 6 7 | 8 | 9 If the box is available put the appropriate X or O in there and switch players, i.e. X becomes O and vice versa. If the box is NOT available warn the user and get another box until they select a valid open box.

Game Over！;

After all spots have been select Display "Game Over!";

。

#include<iostream>

using namespace std;


class TicTacToe {
public:
    void displayBoard();
    void getMove();
    void playGame();
private:
    char board[9];
    char player; // Switch after each move.
};

int main ()
{
    TicTacToe ttt;

    // you need to do the following in a loop 9 times
    ttt.playGame();
}

void TicTacToe::playGame()
{
    getMove();
    // Your implementation here...
}

void TicTacToe::displayBoard()
{
    // Your implementation here...
}

void TicTacToe::getMove()
{
    cout << "Enter Box: ";
    char c;
    cin.get(c);
    if (c > '9' || c < '0')
        // Error message here.

    int number = c - '0';

    cout << "your number is " << number;
    // Your implementation here...
}

推荐答案

您需要一个语句来追加if

you need a statement to go after the if

之后的语句，即使它只是一个;

even if its just a ;

但也许你想要

if (c > '9' || c < '0')
        cout << "Not a Number!";

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