通过Javascript的变量通过AJAX到PHP [英] Pass Javascript variable to PHP via ajax

问题描述

我试图通过从我的javascript code变量转移到服务器端的PHP code。我知道这必须通过Ajax调用它，我相信我已经正确完成，但是访问过我从我的阿贾克斯到我的PHP变量是当我遇到麻烦，因为我是新来的PHP。这是我的code我迄今：

I am trying to pass a variable from my javascript code over to the server side PHP code. I know this must be done via an ajax call which i believe i have done correctly, however accessing the variable i pass from my ajax into my php is when i run into trouble as i am new to php. Here is my code i have thus far:

$(document).ready(function() {

            $(".clickable").click(function() {
                var userID = $(this).attr('id');
                //alert($(this).attr('id'));
                $.ajax({
                    type: "POST",
                    url: 'logtime.php',
                    data: "userID=" + userID,
                    success: function(data)
                    {
                        alert("success!");
                    }
                });
            });
        });

<?php //logtime.php
$uid = isset($_POST['userID']);
//rest of code that uses $uid
?>

我想通过我的JavaScript变量用户ID到PHP（$用户ID），但我已经错了地方公路沿线。感谢您的帮助！

I'm trying to pass my javascript variable "userID" to php ($userID), however i've gone wrong somewhere along the road. Thanks for the help!

推荐答案

传递这样的数据，以Ajax调用（ HTTP： //api.jquery.com/jQuery.ajax/ ）：

Pass the data like this to the ajax call (http://api.jquery.com/jQuery.ajax/):

data: { userID : userID }

和你的PHP做到这一点：

And in your PHP do this:

if(isset($_POST['userID']))
{
    $uid = $_POST['userID'];

    // Do whatever you want with the $uid
}

isset（）函数函数的目的是检查wheter给定的变量存在，不是为了它的价值。

isset() function's purpose is to check wheter the given variable exists, not to get its value.

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