在从sstream变量中提取字符串后，如何获取剩余的字符串？ [英] How do you get the remaining string after a string extracted from a sstream variable?

问题描述

像我有一个 stringstream 变量包含abc gg rrr ff

当我对 stringstream 变量使用>>时，它会给我abc。如何获取剩余的字符串：gg rrr ff？似乎 str（）也不是 rdbuf（）这样工作。

您可以使用 std :: getline 从流中获取其余的字符串：

  #include< iostream> 
 #include< sstream> 
 
 using namespace std; 
 
 int main（）{
 stringstream ss（abc gg rrr ff）; 
 string s1，s2; 
 ss>> s1; 
 getline（ss，s2）; //获取字符串的剩余部分！ 
 cout<< s1<< endl; 
 cout<< s2 < endl; 
 return 0; 
} 
  

输出：

  abc 
 gg rrr ff 
  

演示： a href =http://www.ideone.com/R4kfV> http://www.ideone.com/R4kfV

有一个重载 std :: getline 函数，其中第三个参数接受分隔符，您可以读取该字符串。请参阅 std :: getline 的文档：

• std :: getline

Like I have a stringstream variable contains "abc gg rrr ff"

When I use >> on that stringstream variable, it gives me "abc". How can I get the remaining string: " gg rrr ff"? It seems neither str() nor rdbuf() does this work.

解决方案

You can use std::getline to get the rest of the string from the stream:

#include <iostream>
#include <sstream>

using namespace std;

int main() {
        stringstream ss("abc gg rrr ff");
        string s1, s2;
        ss >> s1;
        getline(ss, s2); //get rest of the string!
        cout << s1 << endl;
        cout << s2 << endl;
        return 0;
}

Output:

abc
gg rrr ff

Demo : http://www.ideone.com/R4kfV

There is an overloaded std::getline function in which a third parameter takes a delimiter upto which you can read the string. See the documentation of std::getline:

• std::getline

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