为什么C ++不打印char的内存地址，但打印int或bool？ [英] Why C++ would not print the memory address of a char but will print int or bool?

问题描述

可能重复：

为什么不显示字符数据的地址？

下面是代码和输出：

int main(int argc, char** argv) {

    bool a;
    bool b;

    cout<<"Address of a:"<<&a<<endl;
    cout<<"Address of b:"<<&b<<endl;

    int c;
    int d;

    cout<<"Address of c:"<<&c<<endl;
    cout<<"Address of d:"<<&d<<endl;

    char e;    
    cout<<"Address of e:"<<&e<<endl;

    return 0;
}

输出：

地址a：0x28ac67

Address of a:0x28ac67

地址b：0x28ac66

Address of b:0x28ac66

地址c：0x28ac60

Address of c:0x28ac60

地址d：0x28ac5c

Address of d:0x28ac5c

地址e：

我的问题是：
其中是char的内存地址？为什么不打印？

My question is: Where is the memory address of the char? And why is it not printed?

谢谢。

推荐答案

我怀疑重载 - char * 版本 ostream :: operator<< 期望一个NUL终止的C字符串 - 只传递一个字符的地址，所以你在这里是未定义的行为。您应该将地址转换为 void * ，以便打印所期望的内容：

I suspect that the overloaded-to-char * version of ostream::operator<< expects a NUL-terminated C string - and you're passing it only the address of one character, so what you have here is undefined behavior. You should cast the address to a void * to make it print what you expect:

cout<<"Address of e:"<< static_cast<void *>(&e) <<endl;

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