这是std :: get_time的一个错误？ [英] is this a bug in std::get_time?

问题描述

我试图解析一个日期时间字符串，并将结果放入std :: tm结构。下面是代码，

I am trying to parse a date-time string and put the result into a std::tm structure. Below is the code,

#include <iomanip>
#include <ctime>
#include <sstream>
#include <string>

std::stringstream ss;
struct std::tm when;

ss.str("8/14/2015 3:04:23 PM");
ss >> std::get_time(&when, "%m/%d/%Y %r");

运行代码后，when.tm_hour是27.这是一个错误，错误？

After run the code, the when.tm_hour is 27. Is this a bug, or I did something wrong?

我在Windows 7上使用Visual Studio 2013.

I am using Visual Studio 2013 on windows 7.

$ b

推荐答案

您正在遇到一个错误，Microsoft的实现 std :: num_get :: do_get 函数，特别是解析AM / PM（％p ）部分的部分：

You are running into a bug in Microsoft's implementation of the std::num_get::do_get function, specifically the section which parses the AM/PM (%p) part of the time:

    case 'p':
        _Ans = _Getloctxt(_First, _Last, (size_t)0, ":AM:am:PM:pm");
        if (_Ans < 0)
            _State |= ios_base::failbit;
        else
            _Pt->tm_hour += _Ans * 12;
        break;

问题是_Getloctxt在范围[0,3]中返回一个int，范围[0,1]。

The problem is that _Getloctxt returns an int in the range [0,3] and not in the expected range [0,1].

此错误已报告给Microsoft（ID： 808162 ）谁声称已在Visual Studio 2015中修复它。

This bug has been reported to Microsoft (ID:808162) who claim to have fixed it in Visual Studio 2015.

这篇关于这是std :: get_time的一个错误？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！