boost scoped_ptr的C ++多态性 [英] C++ polymorphism with boost scoped_ptr

问题描述

为什么下列代码不允许调用foo（ptr）？

Why does the following code not allow foo(ptr) to be called ?

#include <boost/scoped_ptr.hpp>
struct A {
    virtual ~A() {}
};

struct B: public A {};

void foo(boost::scoped_ptr<A>& a) {}

void goo(A& a) {}
int main() {
    boost::scoped_ptr<B> ptr(new B);
    foo(ptr);
    B b;
    goo(b);
}

我们传递引用的对应表单按预期工作。我们不应该用boost scoped_ptr来做多态性
？

The corresponding form where we pass references works as expected. Are we supposed not to do polymorphism with boost scoped_ptr ?

g ++ with boost 1.49给我：

g++ with boost 1.49 gives me:

error: invalid initialization of reference of type ‘boost::scoped_ptr<A>&’ from expression of type ‘boost::scoped_ptr<B>’

推荐答案

这是因为 foo 某些原因，通过引用获取一个作用域指针 。这是完全不必要的，是呼叫失败的原因。有从 scoped_ptr< B> 到 scoped_ptr< A> 的转换，但不是 scoped_ptr< ; B>& 到 scoped_ptr< A>& 。

That's because foo, for some reason, takes a scoped pointer by reference. That is completely unnecessary and is the reason why the call fails. There is a conversion from scoped_ptr<B> to scoped_ptr<A> but not from scoped_ptr<B>& to scoped_ptr<A>&.

传递它作为const的引用。

You should pass it as reference to const.

void foo(boost::scoped_ptr<A> const & a) {}

顺便说一下，这不是智能指针本身的问题。以下代码的失败原因与您的原因相同。

Incidentally, this isn't a "problem" of smart pointers per se. The following code fails for the same reasons as yours.

void foo(A*& p) {}
int main()
{
    B* p = new B;
    foo(p); //FAIL
}

为了解决这个问题，你必须传递指针值，或者，如果你足够的变态，通过引用const

In order to fix this you have to pass the pointer either by value, or, if you're sufficiently perverted, by reference to const

 void foo (A * const & p); // <-- a perv wrote this

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