C ++中的本地/静态变量作用域 [英] Local/static variable scope in C++

问题描述

如果我写这样：

#include <iostream>

int main()
{
    using namespace std;

    {int n;n=5;} cout<<n;
    system("pause");
    return 0;
}

编译器告诉我n是未声明的。然后我试图使其静态，但是，再次，编译器告诉我，它是未申报。不是变量声明的静态有程序范围？

The compiler tells me that n is undeclared. Then I tried making it static, but again, the compiler tells me that it is undeclared. Doesn't a variable declated static have program scope? If not, how do I use n in this program?

推荐答案

你的范围与生命周期混淆。静态变量的生命周期等于程序的生命周期，但它们仍然遵循基于声明位置的范围规则。

You're confusing scope with lifetime. Static variables have a lifetime equal to the program's lifetime, but they still follow scoping rules based on where they are declared.

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