内部类中的引用成员的默认赋值运算符 [英] Default assignment operator in inner class with reference members

问题描述

我遇到了一个我不明白的问题，我希望这里的人能提供一些见解。简化代码如下（原始代码是自定义队列/队列迭代器实现）：

I've run into an issue I don't understand and I was hoping someone here might provide some insight. The simplified code is as follows (original code was a custom queue/queue-iterator implementation):

class B
{
public:
    B() {};
    class C
    {
    public:
        int get();
        C(B&b) : b(b){};
    private:
        B& b;
    };
public:
    C get_c() { return C(*this); }
};

int main()
{
    B b;
    B::C c = b.get_c();


    c = b.get_c();
    return EXIT_SUCCESS;
}

编译时会出现以下错误：

This, when compiled, gives me the following error:

foo.cpp: In member function 'B::C& B::C::operator=(const B::C&)':
foo.cpp:46: error: non-static reference member 'B& B::C::b', can't use default assignment operator
foo.cpp: In function 'int main()':
foo.cpp:63: note: synthesized method 'B::C& B::C::operator=(const B::C&)' first required here

可以通过使用两个单独的C变量，因为它们应该是独立的C对象，但这只是隐藏的问题（我仍然不明白为什么我不能这样做）。

I can go around this by using two separate C variables, as they are supposed to be independent 'C' objects, but this only hides the problem (I still don't understand why I can't do this).

我认为原因是引用不能被复制，但我不明白为什么。我需要提供自己的赋值运算符和复制构造函数吗？

I think the reason is that the reference cannot be copied, but I don't understand why. Do I need to provide my own assignment operator and copy constructor?

推荐答案

这个问题与内部类无关。在C ++中，你不能（重新）分配引用 - 它们需要在定义时初始化。

This problem has nothing to do with inner classes. In C++ you just can't (re)assign references - they need to be initialised when defined.

一个更简单的例子是：

class B
{
public:
    B(int& i) : ir(i) {};

    int& ir;
};


int main()
{
    int i;
    B b(i);      // Constructor - OK

    int j;
    B bb = B(j); // Copy constructor - OK

    bb = b;      // Assignment - Error
    return 0;
}

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