将精度double转换为字符串 [英] Converting a precision double to a string

问题描述

我有一个大数字在c ++存储为一个精确的double值（假设输入'n'是75）：2.4891e + 109

I have a large number in c++ stored as a precise double value (assuming the input 'n' is 75): 2.4891e+109

这里是我的代码到目前为止，虽然它不完全相关的问题：

Here's my code so far, although it's not entirely relevant to the question:

int main(){

    double n = 0; 
    cout << "Giz a number: ";
    cin >> n;
    double val = 1;
    for(double i = 1; i <= n; i++){
        val = val * i;
    }
    //Convert val to string/array here?
}

推荐答案

std::stringstream str;
str << fixed << setprecision( 15 ) << yournumber;

您也可能对科学格式标志。

C ++ 11也有一些有趣的函数 std :: to_string ，您可以查看！

C++11 also has a few interesting functions std::to_string which you may want to check out!

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