将精度double转换为字符串 [英] Converting a precision double to a string

问题描述

我有一个大量的c ++存储为一个精确的双值（假设输入'n'为75）：2.4891e + 109

有没有办法将它转换成每个个人数字的字符串或数组？

这是我的代码到目前为止，虽然这与问题不完全相关：

  int main（）{
 
 double n = 0; 
 cout<<< Giz一个数字：; 
 cin>> N; 
 double val = 1; 
 for（double i = 1; i< = n; i ++）{
 val = val * i; 
} 
 //将val转换为字符串/数组？ 
} 
  

解决方案

  std :: stringstream str; 
 str<<<固定的< setprecision（15）<<你的号码; 
  

您可能还对科学感兴趣格式标志。

C ++ 11还有一些有趣的功能 std :: to_string ，您可能需要检查！

I have a large number in c++ stored as a precise double value (assuming the input 'n' is 75): 2.4891e+109

Is there any way to convert this to a string or an array of each individual digit?

Here's my code so far, although it's not entirely relevant to the question:

int main(){

    double n = 0; 
    cout << "Giz a number: ";
    cin >> n;
    double val = 1;
    for(double i = 1; i <= n; i++){
        val = val * i;
    }
    //Convert val to string/array here?
}

解决方案

std::stringstream str;
str << fixed << setprecision( 15 ) << yournumber;

You may also be interested in the scientific format flag.

C++11 also has a few interesting functions std::to_string which you may want to check out!

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