类作为函数c ++的参数 [英] Classes as parameter of function c++

问题描述

我写了一堆加密算法作为类，现在我想实现加密模式（广义模式显示在维基百科，而不是具体的算法的规格）。我如何写一个可以接受任何类的函数？

I wrote a bunch of crypto algorithms as classes and now I want to implement encryption modes (generalized modes shown in wikipedia, not the specific ones in the algorithms' specifications). How would I write a function that can accept any of the classes?

编辑：

完成

class mode{
  private:
    algorithm_class

  public:
    mode(Algorithm_class, key, mode){
       algorithm_class = Algorithm_class(key, mode);

    }

};

推荐答案

b

template<class AlgorithmType>
class mode{
  private:
    AlgorithmType _algo;

  public:
    mode(const AlgorithmType& algo)
      : _algo(algo) {}
};

？

不需要 mode 和键参数，因为算法可以由用户创建：

No need for mode and key parameters, as the algorithm can be created by the user:

mode<YourAlgorithm> m(YourAlgorithm(some_key,some_mode));

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