计时器计时器不正确转换秒数 [英] Chrono Timer Not Converting Seconds Properly
问题描述
我有一个有趣的,但奇怪的问题,我的游戏计时器。它似乎毫秒工作正常。但是,当我尝试应用 std :: chrono :: seconds
cast时,突然获取 0.000000
浮动。
我的计时器如下:
#include< ; iostream>
#include< time.h>
#include< chrono>
class Timer
{
public:
typedef std :: chrono :: high_resolution_clock时间;
typedef std :: chrono :: milliseconds ms; //< - 如果改变为秒,我得到0.00000
typedef std :: chrono :: duration< float> fsec;
std :: chrono :: high_resolution_clock :: time_point m_timestamp;
float currentElapsed;
Timer()
{
m_timestamp = Time :: now();
}
float getTimeElapsed()
{
return currentElapsed;
}
void Tick()
{
currentElapsed = std :: chrono :: duration_cast< ms>(Time :: now() - m_timestamp).count ();
m_timestamp = Time :: now();
}
public:
// Singleton stuff
static Timer * Instance();
static void Create();
};
计时器每帧一次所以,例如我通常每帧大约33ms。 33ms / 1000 = 0.033s
秒,所以应该有足够的位空间。
编辑:对不起,秒,不是毫秒
std :: chrono :: seconds
都被指定为具有整数表示(C ++ 11§20.11.2[time.syn])。当您将高分辨率持续时间转换为低分辨率持续时间时,您正在执行带有结果截断的整数除法,例如
使用命名空间std :: chrono;
assert(duration_cast< seconds>(milliseconds {999})== seconds {0});
您可以通过在缩放之前切换到浮点表示而不是之后的:
using namespace std :: chrono;
currentElapsed = duration_cast< duration< float,std :: milli>>(Time :: now() - m_timestamp).count();
更好的是, store currentElapsed
作为 duration
大小:
class Timer {
typedef std :: chrono :: high_resolution_clock时间;
typedef std :: chrono :: duration< float>持续时间;
Time :: time_point m_timestamp;
duration currentElapsed;
public:
Timer():m_timestamp(Time :: now()){}
duration getTimeElapsed()const {
return currentElapsed;
}
void Tick(){
auto now = Time :: now();
currentElapsed = now - m_timestamp;
m_timestamp = now;
}
};
I am having an interesting, yet strange issue with my game timer. It seems like the milliseconds works just fine. However, when I try to apply the std::chrono::seconds
cast I suddenly get 0.000000
when casting to a float.
My timer is as follows:
#include <iostream>
#include <time.h>
#include <chrono>
class Timer
{
public:
typedef std::chrono::high_resolution_clock Time;
typedef std::chrono::milliseconds ms; //<--If changed to seconds, I get 0.00000
typedef std::chrono::duration<float> fsec;
std::chrono::high_resolution_clock::time_point m_timestamp;
float currentElapsed;
Timer()
{
m_timestamp = Time::now();
}
float getTimeElapsed()
{
return currentElapsed;
}
void Tick()
{
currentElapsed = std::chrono::duration_cast<ms>(Time::now() - m_timestamp).count();
m_timestamp = Time::now();
}
public:
//Singleton stuff
static Timer* Instance();
static void Create();
};
The timer gets ticked once per frame. So, for instance I normally get about 33ms per frame. 33ms / 1000 = 0.033s
seconds so there should be plenty of bit space to hold that.
Any ideas on what maybe going on?
Any help is greatly appreciated!
EDIT: Sorry, Seconds, not Milliseconds
std::chrono::seconds
et al. are all specified to have integral representations (C++11 §20.11.2 [time.syn]). When you convert a high-resolution duration to a low-resolution duration, you are performing integer division with resulting truncation, e.g,
using namespace std::chrono;
assert(duration_cast<seconds>(milliseconds{999}) == seconds{0});
You can avoid this truncation by switching to a floating point representation before scaling instead of after:
using namespace std::chrono;
currentElapsed = duration_cast<duration<float,std::milli>>(Time::now() - m_timestamp).count();
Better yet, store currentElapsed
as a duration
to keep the "units" associated with the magnitude:
class Timer {
typedef std::chrono::high_resolution_clock Time;
typedef std::chrono::duration<float> duration;
Time::time_point m_timestamp;
duration currentElapsed;
public:
Timer() : m_timestamp(Time::now()) {}
duration getTimeElapsed() const {
return currentElapsed;
}
void Tick() {
auto now = Time::now();
currentElapsed = now - m_timestamp;
m_timestamp = now;
}
};
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