在C ++中静态初始化匿名联合 [英] Statically initialize anonymous union in C++

问题描述

我试图在Visual Studio 2010中静态初始化以下结构：

I am trying to statically initialize the following structure in Visual Studio 2010:

struct Data
{
   int x;
   union
   {
      const Data* data;
      struct {int x; int y; };
   };
};

以下是失败与错误C2440：'initializing'：无法转换'data *'to'char'。

static Data d1;
static Data d = {1, &d1};
static Data d2 = {1, {1, 2}};

我找到了一些方法的引用，这可以正确初始化，但没有一个在VS2010工作。任何想法？

I have found references to some ways this can be initialized properly but none of them work in VS2010. Any ideas?

推荐答案

你能通过定义重载的构造函数来实现吗？未验证的代码：

Can you do it by defining overloaded constructors? Untested code ahead:

struct Data 
{ 
    int x; 
    union 
    { 
        const Data* data; 
        struct {int a; int b; } z; 
    } y;

    Data()
    {
        x = 0;
        y.data = 0;
        y.z.a = 0;
        y.z.b = 0;
    }

    Data(int x_, Data* data_)
    {
        x = x_;
        y.data = data_;
    }

    Data(int x_, int a_, int b_)
    {
        x = x_;
        y.z.a = a_;
        y.z.b = b_;
    }
}; 

static Data d1; 
static Data d(1, &d1); 
static Data d2(1, 1, 2); 

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