是< random>库在c ++ 11可移植？ [英] Is the <random> library in c++11 portable?

问题描述

库是否在c ++ 11可移植？

Is the library in c++11 portable? I have avoided rand() because I heard it wasn't portable.

推荐答案

如何定义可移植？

如果通过portable，你的意思是将产生相同输入的随机数的二进制相同序列，则是， rand 不可移植。是的， C ++随机数生成器是可移植的（大多数不是 std :: default_random_engine 或 std :: random_device ），因为它们实现了特定算法。 rand 可以是任何东西，只要它不完全不同于随机数字生成器。

If by "portable", you mean "will produce binary identical sequences of random numbers given the same input", then yes, rand isn't portable. And yes, the C++ random generators are portable (most of them. Not std::default_random_engine or std::random_device), because they implement specific algorithms. rand is allowed to be anything, as long as it's not entirely unlike a random number generator.

，正如@PeteBecker指出的，分布本身没有这么好定义。因此， std :: mt19937 会为给定的种子产生相同的值序列，不同 std :: uniform_int_distribution 可以为同一输入序列和范围提供不同的值。

That being said, as @PeteBecker pointed out, the distributions themselves are not so well-defined. So while std::mt19937 will produce the same sequence of values for a given seed, different std::uniform_int_distributions can give different values for the same input sequence and range.

当然，如果你需要一致性，你总是可以定义自己的分布。

Of course, if you need consistency, you can always define your own distribution.

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