无法从括号括起来的初始化程序列表转换为std :: vector [英] Could not convert from brace-enclosed initializer list to std::vector

问题描述

我看到了很多类似的问题，但我不认为我看到了相同的问题。这是很基本的。我的讲师的一些代码未能编译，我把问题提炼到这个测试用例：

  void foo（vector< int> ; v）{
} 
 
 void fooUsage（）{
 foo（{0，1，2}）; 
} 
  

此操作失败：

无法将'{0,1,2}'从'<括号括起始化程序列表>'转换为'std :: vector< int> p>

注意：它适用于GCC 5.0.0 20141228，但在我的GCC 4.7.1（tdm-1）上失败。

对不起，如果这太基础，但我不知道C ++ 11很好。

解决方案

原来，我只需要在gcc命令行中添加 -std = c ++ 11 。

注意：我错误地认为这是默认开启，因为我也得到一些警告，像这样：

扩展初始化列表可以使用-std = c ++ 11或-std = gnu ++ 11 [默认启用]

默认？这是误导我的。

I saw a lot of similar questions, but I don't think I saw quite the same one. It's pretty basic. Some code from my lecturer is failing to compile, and I distilled the problem to this test case:

void foo(vector<int> v) {
}

void fooUsage() {
    foo({0, 1, 2});
}

This fails with:

could not convert '{0, 1, 2}' from '<brace-enclosed initializer list>' to 'std::vector<int>

Note: It works on GCC 5.0.0 20141228 but fails on my GCC 4.7.1 (tdm-1).

Sorry if this is too basic but I don't know C++11 very well.

解决方案

It turns out I only needed to add -std=c++11 to the gcc command line.

Note: I was mistakenly thinking that this is on by default, since I was also getting some warnings like this:

extended initializer lists only available with -std=c++11 or -std=gnu++11 [enabled by default]

See how it says "enabled by default"? That's what was misleading me.

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