用括号括起来的初始化器列表初始化结构时出错 [英] Error when initializing a struct with a brace-enclosed initializer list

问题描述

struct CLICKABLE
{
    int x;
    int y;
    BITMAP* alt;
    BITMAP* bitmap;

    CLICKABLE()
    {
        alt=0;
    }
};

CLICKABLE input={1,2,0,0};

此代码给我以下错误:

无法从括号括起来的初始化程序列表中进行转换

Could not convert from brace-enclosed initializer list

有人可以解释一下为什么编译器会给我这个错误，以及我该如何解决?我还在学习语言.

Could someone explain me why the compiler is giving me this error, and how I can fix it? I'm still learning the language.

推荐答案

您的类具有构造函数，因此它不是聚合的，这意味着您不能使用聚合的初始化.您可以添加具有正确数量和类型的参数的构造函数:

Your class has a constructor, so it isn't an aggregate, meaning you cannot use aggregate initialization. You can add a constructor taking the right number and type of parameters:

struct CLICKABLE
{
  int x;
  int y;
  BITMAP* alt;
  BITMAP* bitmap;

  CLICKABLE(int x, int y, BITMAP* alt, BITMAP* bitmap) 
  : x(x), y(y), alt(alt), bitmap(bitmap) { ... }

  CLICKABLE() : x(), y(), alt(), bitmap() {}

};

或者，您可以删除用户声明的构造函数，并使用聚合初始化:

Alternatively, you can remove the user declared constructors, and use aggregate initialization:

CLICKABLE a = {};         // all members are zero-initialized
CLICKABLE b = {1,2,0,0};

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