如何获取Windows中的显示数量？ [英] How do I get the number of displays in windows?

问题描述

我想计算活动显示的数量。对于Mac我可以使用以下：

I want to count the number of active displays. For Mac I can use the following:

CGDisplayCount nDisplays;
CGGetActiveDisplayList(0,0, &nDisplays);
log.printf("Displays connected: %d",(int)nDisplays);

如何在Windows中实现相同的功能？我找到了 EnumDisplayMonitors ，但我找到了

How can I achieve the same in Windows? I've found EnumDisplayMonitors but I can't work out how to use it.

推荐答案

正如您所发现的， EnumDisplayMonitors（） 会做这项工作，但它是一个有点棘手的调用。该文档声明：

As you have discovered, EnumDisplayMonitors() will do the job but it is a little tricky to call. The documentation states:

EnumDisplayMonitors函数枚举显示监视器（包括与镜像驱动程序关联的不可见伪监视器）指定剪切矩形与设备上下文的可见区域的交集。 EnumDisplayMonitors为枚举的每个监视器调用一个应用程序定义的MonitorEnumProc回调函数。注意GetSystemMetrics（SM_CMONITORS）只计算显示监视器。

The EnumDisplayMonitors function enumerates display monitors (including invisible pseudo-monitors associated with the mirroring drivers) that intersect a region formed by the intersection of a specified clipping rectangle and the visible region of a device context. EnumDisplayMonitors calls an application-defined MonitorEnumProc callback function once for each monitor that is enumerated. Note that GetSystemMetrics (SM_CMONITORS) counts only the display monitors.

这使我们更容易的解决方案： GetSystemMetrics（SM_CMONITORS） 。事实上，如果你有psuedo监视器，这可能比 EnumDisplayMonitors（）更好。

This leads us to an easier solution: GetSystemMetrics(SM_CMONITORS). Indeed this may be even better than EnumDisplayMonitors() if you have psuedo-monitors.

如下调用 EnumDisplayMonitors（）尝试：

BOOL CALLBACK MonitorEnumProc(HMONITOR hMonitor, HDC hdcMonitor, LPRECT lprcMonitor, LPARAM dwData)
{
    int *Count = (int*)dwData;
    (*Count)++;
    return TRUE;
}

int MonitorCount()
{
    int Count = 0;
    if (EnumDisplayMonitors(NULL, NULL, MonitorEnumProc, (LPARAM)&Count))
        return Count;
    return -1;//signals an error
}

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