如何获得一个指向编译器选择的重载函数的函数指针？ [英] How to get a function pointer to the overloaded function that the compiler chooses?

问题描述

如何获得一个函数指针，指向编译器在检查参数后选择的重载函数？在此示例中：

How can I get a function pointer to the overloaded function that the compiler would choose after inspecting the arguments? In this example:

#include <iostream>

void MyFunction(float a){}
void MyFunction(int a){}

int main()
{
  float a;

  MyFunction(a);

  void (*manualFunctionPointer)(float);
  manualFunctionPointer(a);

  // automaticFunctionPointer = ?
}

我已经指定我想要一个函数指针，并返回void。编译器肯定可以自己计算出来，因为MyFunction（a）调用调用正确的函数。有没有办法获得一个函数指针指向编译器选择的函数？

I have specified that I want a function pointer to the function that accepts a float and returns void. The compiler can certainly figure that out by itself, because the MyFunction(a) call calls the right function. Is there a way to get a function pointer to the function that the compiler chooses?

推荐答案

Replace the float in

void (*manualFunctionPointer)(float);

使用

void (*manualFunctionPointer)(decltype(a));

然后无论什么改变，manualFunctionPointer将会跟随

Then whatever a changes too, manualFunctionPointer will follow

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