在Windows中通过串行写入二进制数据 [英] Writing binary data over serial in windows

问题描述

我需要通过串口发送二进制数据，没有任何字节在重新解释为控制字符。我目前正在设置我的串口如下：

I need to send binary data over a serial port, without any bytes getting reinterpreted as control characters along the way. I'm currently setting up my serial port as follows:

#include <windows.h>

// open serial port
HANDLE hSerial;
hSerial = CreateFile ("COM1", GENERIC_READ | GENERIC_WRITE, 0, 0, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, 0);

// get serial parameters
DCB dcbSerialParams = {0};
dcbSerialParams.DCBlength = sizeof (dcbSerialParams);
if (!GetCommState(hSerial, &dcbSerialParams)) {
    cout << "error getting state\n";
    exit(0);
}

// set serial params
dcbSerialParams.BaudRate = CBR_115200;
dcbSerialParams.ByteSize = 8;
dcbSerialParams.StopBits = ONESTOPBIT;
dcbSerialParams.Parity   = NOPARITY;
if (!SetCommState (hSerial, &dcbSerialParams)) {
    cout << "error setting parameters\n";
    exit(0);
}

// set time outs
COMMTIMEOUTS timeouts = {0};
timeouts.ReadIntervalTimeout = 50;
timeouts.ReadTotalTimeoutConstant = 10;
timeouts.ReadTotalTimeoutMultiplier = 10;
timeouts.WriteTotalTimeoutConstant = 10;
timeouts.WriteTotalTimeoutMultiplier = 10;
if (!SetCommTimeouts (hSerial, &timeouts)) {
    cout << "problem setting timeout values\n";
    exit(0);
} else cout << "timeouts set\n";

当我发出ReadFile命令，我可以得到和显示从0到255的字节没有问题。但我没有这样的运气与WriteFile。是否有明确设置二进制写入模式的方法？

When I issue ReadFile commands, I can get and display bytes from 0 to 255 with no problem. but I'm having no such luck with WriteFile. Is there a way to explicitly set a binary write mode?

EDIT

好的，这里有一些更多的信息。我有一台windows机器和一个linux单板计算机通过串口连接，上面的代码在windows上是后面是：

Ok, here's some more info. I have a windows machine and a linux single board computer hooked up through serial, the code above on the windows side is followed by:

unsigned char temp = 0;

bool keepReading = true;
while (keepReading) {
    DWORD dwBytesRead = 0;
    ReadFile (hSerial, &temp, 1, &dwBytesRead, NULL);
    if (1 == dwBytesRead) cout << (unsigned int) temp << " ";
    if (255 == temp) keepReading = false;
}
cout << endl;

bool keepWriting = true;
char send = 0;
while (keepWriting) {
    DWORD dwBytesWritten = 0;
    WriteFile (hSerial, &send, 1, &dwBytesWritten, NULL);
    send++;
    if (256 == send) keepWriting = false;
}

我的linux端代码看起来像这样：

My code on the linux side looks like this:

int fd = open("/dev/ttymxc0", O_RDWR | O_NOCTTY);
struct termios options;
bzero (options, sizeof(options));
options.c_cflag = B115200 | CS8 | CLOCAL | CREAD;
options.c_iflat = IGNPAR;
options.c_oflag = 0;
options.c_lflag = ICANON;
options.c_cc[VMIN] = 1;
options.c_CC[VTIME] = 0;
tcflush (fd, TCIFLUSH);
tcsetattr (fd, ICSANOW, &options);

bool keepWriting = true;
char send = 0;
while (keepWriting) {
    write (fd, &send, 1);
    send++;
    if (256 == send) keepWriting = false;
}

bool keepReading = true;
while (keepReading) {
    char temp = 0;
    int n = read (fd, &temp, 1);
    if (-1 == n) {
        perror ("Read error");
        keepReading = false;
    } else if (1 == n) {
        cout << temp << " ";
    }
    if (256 == temp) keepReading = false;

}
cout << endl;

close(fd);

我在两台机器上启动代码，第一组while循环运行良好。窗口侧的终端显示0到255.然后它只是坐在那里。如果我输出在linux端为第二组while循环读取的字节数，它不断地给我0字节。

I start up the code on both machines, and the first set of while loops runs fine. The terminal on the windows side displays 0 through 255. Then it just sits there. If I output the number of bytes read on the linux side for the second set of while loops, it continually gives me 0 bytes. This would indicate a closed port normally, but I just sent a bunch of info through it so how could that be?

推荐答案

好吧，这是一个封闭的端口，但是我只是通过它发送了一堆信息。所以我想出来了，而是一个同事。在linux端，在/ etc / inittab文件中我不得不注释掉这行：

Alright so I figured it out, rather, a co-worker did. On the linux side, in the file /etc/inittab I had to comment out the line:

T0:23:respawn:/sbin/getty -L ttymxc0 115200 vt100

这是抓住串口，不能用于接收字节。我现在看到预期的输出。

This was grabbing the serial port in a way that made it unusable for receiving bytes. I now see the expected output.

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